Product of Array Except Self

In this video, we discuss the problem of finding the product of all elements in an array except the current element. We explore multiple approaches to solving this problem, starting with a naive solution that uses nested loops. While this method has a time complexity of O(n^2), we further optimize the solution using the prefix and suffix product arrays, which reduces the time complexity to O(n) with O(n) space. Finally, we introduce an efficient approach that calculates the product using a product array in O(n) time and O(1) space, handling special cases like arrays containing zeros.

The efficient approach tackles arrays with zeros by considering different scenarios. If the array contains no zeros, the product for each element is simply the total product of all elements divided by the current element. For arrays with exactly one zero, the product for the zero's index will be the product of all non-zero elements, and for arrays with more than one zero, the product for all elements will be zero. The video covers each method in detail and provides C++ code implementations for all approaches, including handling edge cases.

For more details, please go through - Product of Array Except Self